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Sergeu [11.5K]
3 years ago
11

Please HELP ME!!! (16 POINTS) due today :)))

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

Step-by-step explanation:

I'm not sure what the question is asking, but if you mean the angles in the blue lines

First one, we know that the full length is 90, and it has gacen us 80, so the angle would be 10

Second one, we see that the angle is still 90, and since the given degree is 30, the unkown angle would be 60

Third one, the given angle is 75 so 90-75=15.

The answers would be 10, 60, and 15.

Zanzabum3 years ago
8 0
Answer:

4. 170*

5. 330*

6. 285*

Step-by-step explanation:

4. Explanation: 90* is added by the other angle in the right + 80* for the same angle

90* + 80* = 170*
————————————————————

5. Explanation: we are trying to find out the total among every angle measure except for 30.

Total angle measure = 360*

360 - 30 = 330*
—————————————————————

6. Explanation: 360 - 75 = 285*


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The second angle of a triangle is 75 more than the first angle. The third angle is three times the first. Find the three angles.
Ray Of Light [21]

Answer:

Angle 1= 63°

Angle 2 = 21°

Angle 3 = 96°

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2 years ago
Find the solution of the given initial value problem in explicit form. y' = (1 – 11x)y?, y(0) = -1 Enclose numerators and denomi
Tanya [424]

Answer:

y(x)=-e^{x-(\frac{11*x^{2} }{2}) }

Step-by-step explanation:

This is a separable equation. First divide both sides by y:

\frac{dy(x)}{\frac{dx}{y(x)} } =-11x+1\\\frac{dy}{y}=(-11x+1)dx

Integrate both sides:

\int\ \frac{dy}{y} \ =\int\ (-11x+1) \, dx

log(y)=-(\frac{11*x}{2} )+x+ c_1

Solve for y taking exp to both sides:

y(x)=c_1*e^{x-(\frac{11*x^{2} }{2}) }

Where c_1 is an arbitrary constant

Evaluating the initial condition:

y(0)=c_1*e^{0-(\frac{11*0^{2} }{2}) } =-1

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A company sells widgets. The amount of profit, y, made by the company, is related to
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Step-by-step explanation:

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<u>Differentiate equation</u>

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<u>Set differentiated equation to zero and solve for x</u>:

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Substitute x = 39 into the equation:

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