Answer:
y = -1/2(x + 4)² + 2 or y = -1/2x²- 4x - 6
Step-by-step explanation:
Given
Vertex = (-4, 2)
The graph passes through the point (-8, -6)
The function in vertex form is:
y = a(x + 4)² + 2
Substitute the coordinates of (-8, -6) and find the value of a:
-6 = a(-8 + 4)² + 2
-8 = 16a
a = -1/2
The function is:
y = -1/2(x + 4)² + 2
or in standard form:
y = -1/2(x² + 8x + 16) + 2 = -1/2x²- 4x - 6
Answer:
2/3
Step-by-step explanation:
Calculators help :)
Choice D
To factor a quadratic equation ax^2+bx+c, find two factors of a and write them in a column, one up, one down. Then find two factors of c and write them in a column. multiply the factors diagonally and add up the products to make b. if the products do not make b, switch the factors up down and try again till you have a match.
in this case,
-1 and 3 are the factors of -3, -5 and 1 are the factors of -15, -1 times 1 is 1, 3 times -5 is -15, -1 and -15 make a sum of -16. so you have (-1x-5)(3x+1)
take the negative sign out you have -(x+5)(3x+1)
I hope I've made myself clear.
Since |x+2| is either positive or zero for x = 2, the domain is set to be all real numbers.
//See the graph.
Answer:
15.02
Step-by-step explanation:
24-8.98
okay so pretty much all you do to make the problem easier is to make the 24 a decimal as well (24.00) than just subtract like this:
24.00
- 8.98
Than once you've set it up like that, subtract. Start in the tenths place which is 0-8. you can't do that so you borrow from the ones place. and that is also 0, so you borrow from 4. than the 4, you cross it out and it turns into a 3, the 0 beside it, cross it out and put a 9 above it because the 0 beside it is borrowing. so now it'll be
23.90
- 8.98 (pretend the far right 0 is crossed out and has a 10 over it)
than you subtract and should get: 15.02
(it sounds weird im sorry explaining over this is complicating)