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igomit [66]
3 years ago
13

A triangle with side lengths of 10, 18, and 30 inches is similar to another triangle. The shortest side of the other triangle ha

s length 3 inches. What is the perimeter, in inches, of the smaller triangle?
Perimeter = 9.5


Perimeter = 10.6


Perimeter = 15.2


Perimeter = 17.4
Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Answer:

wo similar figures have a ratio of 3:5. If 1 side of the smaller figure is 9 ... 12 in. What is the length of LM? x. = 12. 24. A. 13 in. C. 16 in. A. 10 ft. B. 14.4 ft ... How long is the corresponding side of the larger polygon? A. 18 cm. B. 24 cm ... 2. 10. An equilateral triangle has side lengths of 14 inches. Find the altitude of the

Step-by-step explanation:

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Find the value of each card and put them in order, from lowest to highest, 6-8,7-12,1-4,0-1
sergejj [24]

Answer:

6-8=-2

7-12=-5

1-4=-3

0-1=-1

-5, -3, -2, -1

Step-by-step explanation:

Don't get confused with the values after the negative sign the bigger the number after the negative sign, the smaller the value of that number

3 0
3 years ago
What is the volume of a sphere with a radius of 4.5 inches?<br>Use 3.14 for .​
pochemuha

Answer:

V≈381.7in³

Step-by-step explanation:

V=4/3πr³

=4/3•π•4.5³

≈381.70351in³

7 0
3 years ago
What letter is located by the ordered (5,-2)
likoan [24]
I need a diagram to answer
6 0
3 years ago
A parabola can be represented by the equation x2 = -20y.
aliya0001 [1]

Answer:

\mathrm{Parabola\:focus\:given}\:x^2=-20y:\quad \left(0,\:-5\right)

Step-by-step explanation:

Given the equation

x2 = -20y

A parabola is the locus of points such that the distance to a point the focus equals the distance to a line the directrix.

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing parabola with vertex at (h, k), and a focal length |p|.

so

x^2=-20y

\mathrm{Switch\:sides}

-20y=x^2

\mathrm{Factor\:}4

4\cdot \frac{-20}{4}y=x^2

4\left(-5\right)y=x^2

\mathrm{Rewrite\:as}

4\left(-5\right)\left(y-0\right)=\left(x-0\right)^2

\left(h,\:k\right)=\left(0,\:0\right),\:p=-5

Parabola is symmetric around the y-axis and so the focus lies a distance\ p from the center (0, 0) along the y-axis.

\left(0,\:0+p\right)

=\left(0,\:0+\left(-5\right)\right)

\mathrm{Refine}

\left(0,\:-5\right)

Therefore,

\mathrm{Parabola\:focus\:given}\:x^2=-20y:\quad \left(0,\:-5\right)

Please check the attached figure too.

6 0
3 years ago
Read 2 more answers
Katerina draws a square. She wants to draw one line to divide the square into 2 triangles. Is it possible for her to divide the
OleMash [197]
Its not possible to divide the square into two obtuse triangles since each angle within the square is 90 so if you were to draw a line between two of the edges you can only get two right angle trangle.
5 0
3 years ago
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