Question

I need help figuring out this question

Answer 1

Answer:

nre, nre

Step-by-step explanation:

Given

$4b^2 + 16 = 0$

Required

Solve

$4b^2 + 16 = 0$

Subtract 16 from both sides

$4b^2 +16 -16 = 0 - 16$

$4b^2 = - 16$

Divide both sides by 4

$b^2 = -4$

Take square roots of both sides

$b = \sqrt{-4$

$\sqrt{-4} \to$ Complex number

Hence, no real root exist