A sphere with a radius of 21cm JUST fits in a cube-shaped box. Calculate the amount of empty space in the box rounded to the nea rest tenth of a cubic centimetre. How do you solve this?
2 answers:
Answer:
Since its a cube and a sphere just fits in side it we know that both the sphere and the cube are 21cm wide and since its a cube the dimensions of the cube is 21*21*21 giving you 9,261 cm³ then you find the volume of the V=4/3π10³≈4849.04826 now all you have to do is subtract your two totals to get 4411.95174
Step-by-step explanation:
Brₐinliest plz
Answer:
35,295.6 cm^3 to the nearest tenth.
Step-by-step explanation:
The diameter of the sphere = 2*21 = 42.
The volume of the box = 42^3 ( because the dimensions of the box = the diameter of the sphere).
The volume of the sphere = 4/3 π r^3
= 4/3 π 21^3
So the empty space = 42^3 - 4/3 π 21^3
= 35295.615 cm^3.
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