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ser-zykov [4K]
2 years ago
9

Which expression can be modeled using the number line?

Mathematics
1 answer:
uranmaximum [27]2 years ago
6 0

Answer:

iohji

Step-by-step explanation:

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Which equation does the graph of the systems of equations solve?
vredina [299]
Y = 2x + 3
y = -8x + 3
7 0
3 years ago
Find the product of 8.12 and 2.4<br> Plz someone help .
vesna_86 [32]

Answer:

19.488

Step-by-step explanation:

8.12 x 2.4 = 19.488

8 0
3 years ago
Ave had a rectangular garden that is shown below. The garden's area is 32 square feet. The length of the width is 4 feet. What i
Arlecino [84]

Answer:

The length of Ave's garden is 8 feet.

Step-by-step explanation:

The area of a rectangle can be calculated by:

              A = l × w

Where; A represents the area, l the length and w, width.

Thus from the question,

          32 =  l × 4

           l = 32 /4

           l = 8

Therefore, the length of the garden required is 8 feet.

4 0
3 years ago
Read 2 more answers
The width of a rectangle measures (5v-10w)centimeters, and its length measures (2v+3w)centimeters. Which expression represents t
kiruha [24]

Answer:the perimeter of the rectangle =A) (−14w+14v) centimeters

Step-by-step explanation:

Step 1

The perimeter of a Rectangle is given as 2 (l+ w)

If Length = 2v+3w centimeters.

and width =5v-10wcentimeters

Then Perimeter =2 (2v+3w + 5v-10w)

Perimeter=2(7v -7w)

Perimeter= 14v - 14w or can be written as -14w +14v

8 0
3 years ago
Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of
Kruka [31]

Answer:

Lola was in lead for \frac{6}{25} of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}

\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}

\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}

\text{Fraction for which Lola was in lead}=\frac{6}{25}

Therefore, Lola was in lead for \frac{6}{25} of a mile.

7 0
3 years ago
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