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Svetlanka [38]
3 years ago
12

What type of angels are shown​

Mathematics
2 answers:
sergey [27]3 years ago
5 0
Consecutive Interior
dimaraw [331]3 years ago
3 0

Answer:

? and 46 degrees are same side interior angles.

They are supplementary in that their sum is 180 degrees.

FYI:      ? = 180-46 = 136 degrees

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The area of a square is 4x^2 + 24x + 36. What expression
ss7ja [257]

Answer:

2x + 6

Step-by-step explanation:

The area of a square is the square of the side length:

A = s²

We know that the area of the square is 4x² + 24x + 36.

4 is 2², and 36 is 6².  24 is double 2 times 6.

Therefore, this is a perfect square trinomial:

A = 4x² + 24x + 36

A = (2x + 6)²

Therefore:

s = 2x + 6

7 0
4 years ago
Can someone help please? this is due soon. ill give brainliest
Iteru [2.4K]
Not sure but I think it’s B
4 0
3 years ago
Read 2 more answers
A 15 foot ladder is leaned against a wall. The foot of the ladder makes an
Molodets [167]

Answer:

14.9

Step-by-step explanation:

Sin(58) × 15 = X

X = 14.89

round to the nearest tens

X = 14.9

8 0
4 years ago
Cost of an oil change: $18.00; Markup: 3/4 answers
hjlf
I am assuming that the cost of an oil change already includes the mark-up.

So, 18 is 175%.  18 ÷ 1.75 = 10.29 is the original cost.

10.29 * 3/4 = 30.87/4 = 7.71 mark-up
10.29 + 7.71 = 18

Or if 18 is the basis of the mark-up, then,

18 * 3/4 = 54/4 = 13.50 mark-up
18 + 13.50 = 31.50 new cost of an oil change

8 0
4 years ago
Why do the functions f(x) = sin−1(x) and g(x) = cos−1(x) have different ranges?
Gnom [1K]
We Know that
For a function to have an inverse function, it must be one-to-one—that is, it must pass the Horizontal Line Test.

1. On the interval [–pi/2, pi/2], the function y = sin x is increasing
2. On the interval [–pi/2, pi/2], y = sin x takes on its full range of values, [–1, 1]
3. On the interval [–pi/2, pi/2], y = sin x is one-to-one
sin x has an inverse function on this interval [–pi/2, pi/2]

On the restricted domain [–pi/2, pi/2]  y = sin x has a unique inverse function called the inverse sine function. <span>f(x) = sin−1(x)
</span>the range of y=sin x  in the domain [–pi/2, pi/2]  is [-1,1] 
the range of y=sin-1  x  in the domain [-1,1]  is [–pi/2, pi/2]  

1. On the interval [0, pi], the function y = cos x is decreasing
2. On the interval [0, pi], y = cos x takes on its full range of values, [–1, 1]
3. On the interval [0, pi], y = cos x is one-to-one
cos x has an inverse function on this interval [0, pi]

On the restricted domain [0, pi]  y = cos x has a unique inverse function called the inverse sine function. f(x) = cos−1(x)
the range of y=cos x  in the domain [0, pi]  is [-1,1] 
the range of y=cos-1  x  in the domain [-1,1]  is [0, pi] 

the answer is

<span>the values ​​of the range are different because the domain in which the inverse function exists are different</span>  
8 0
3 years ago
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