All categories

2 years ago

Ian'sbirthdaypartycosts

Mathematics

1 answer:

Ymorist [56]2 years ago

8 0

Answer:

Step-by-step explanation:

10 + 4 = 14 total cost

$26 is his total budget. so,

26 ÷ 14 = 1.85

Ian can only take 1 person because there's not even enough for more. You can only count the whole number.

You might be interested in

Who is the Father Of Math

Assoli18 [71]

Answer: <u>Archimedes</u>

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please does someone know the answer???

Oksana_A [137]

Answer:

Square root of 65

Its c

Please make me the brainliest because I havent got even 1 yet :(

5 0

2 years ago

For which values of k does the system of linear equations have zero, one, or an infinite number of solutions? [Note: not all thr

viktelen [127]

Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

$3x_{1} -x_{2}=2\;\;\;\;\;\;(1)\\ 9x_{1} -3x_{2}=k\;\;\;\;\;(2)$

The system of linear equations can have zero, one, or an infinite number of solutions:

simplify equation (1):

$x_{2}=3x_{1} -2$

substitute in equation (2), we get

$9x_{1} -3(3x_{1}-2)=k\\9x_{1} -9x_{1}+6=k\\0+6=k$

we cannot find the value of $x_{1}$ and $x_{2}$ .

so, there is no solution.

Multiply the equation (1) with 3 and put k is 6,

$3(3x_{1} -x_{2})=3\times2\\9x_{1} -3x_{2})=6$

it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

4 0

2 years ago

59-(2c+3)=4(c+7)+c.

alisha [4.7K]

Step-by-step explanation:

${:}\leadsto$ $\sf 59-(2c+3)=4 (c+7)+c$

${:}\leadsto$ $\sf 59-2c-3=4c+28+c$

${:}\leadsto$ $\sf 56-2c=5c+28$

${:}\leadsto$ $\sf 5c+28=56-2c$

${:}\leadsto$ $\sf 5c+2c=56-28$

${:}\leadsto$ $\sf 7c=28$

${:}\leadsto$ $\sf c={\dfrac {28}{7}}$

${:}\leadsto$ $\sf c=4$

4 0

2 years ago

Read 2 more answers

HELPPPPPP!!!!!!!!!!!!!!!!!

Mnenie [13.5K]

Answer:

The student is wrong.

Step-by-step explanation:

To divide exponents (or powers) with the same base, subtract the exponents. In the second step, the wrong result is calculated.

$\frac{x^{\frac{6}{5}}}{x^{\frac{2}{5}}} = x^{\frac{4}{5}}$

7 0

2 years ago