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MAVERICK [17]
2 years ago
11

Help please very much

Mathematics
1 answer:
Norma-Jean [14]2 years ago
3 0

Answer:

D

Step-by-step explanation:

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University dean is interested in determining the proportion of students who receive some sort offinancial aid. rather than exami
vladimir2022 [97]
The confidence interval is
0.59\pm0.081

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Next we find the z-score associated with this level of confidence:
Convert 98% to a decimal: 98% = 98/100 = 0.98
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Divide by 2:  0.02/2 = 0.01
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Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 2.33.

The margin of error (ME) is given by
ME=z\sqrt{\frac{p(1-p)}{n}}
\\
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This gives us the confidence interval 
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8 0
3 years ago
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