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3 years ago

HELP ME PLEASE IM BEGGING

Mathematics

2 answers:

agasfer [191]3 years ago

8 0

95 is the area
Hope this helps :p

PSYCHO15rus [73]3 years ago

3 0

Answer:

Step-by-step explanation:

what's the problem

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4. In Ghana the high temperatures in degrees Fahrenheit for five days in January were -14°

S_A_V [24]

Answer:

Step-by-step explanation:

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3 years ago

Mrs.Hall records the heights of 50 students in a spreadsheet. The mean height is 68 inches. After looking at the data again, she

son4ous [18]

After removing the outliers, the new total of student heights is
68*50 -82 -86 = 3232
so the new mean is
3232/48 = 67.33

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3 years ago

Rosita is designing a quilt for her bed. She will use 5/8 of the quilt pieces for the background. What percentage of the quilt w

rodikova [14]

5/8 = 0.625
To turn a decimal into a fraction, move the decimal point two spaces to the right.

0.625 = 62.5%

62.5% of the pieces are used for the background

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3 years ago

24 PTS.!!!!!!VERY VERY VERY URGENT PLEASE HELP!!!!!!!! find the least common multiples of 24, 36 and 40 (no listing method!!)

frez [133]

Answer: 360

Step-by-step explanation: don't know how

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3 years ago

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If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers