Can you assist me? Thanks.

Mathematics

1 answer:

MrMuchimi3 years ago

5 0

It’s been a while since I’ve done geometry, but I think this is right.
Because we are dealing with a rhombus: angles X and A are the same, so we use this to solve for x like any other algebraic expression.
After we have found x (24), we can also apply the knowledge that since angles X and M are complementary they will form a 180° line when added.
Substitute the expression for angle X with the solved for expression and subtract it from 180°. And bam! Angle M

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Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$