Find the area of the right triangle.

Please give me some help guys

nasty-shy [4]

Answer:

The answer of this question is 50

7 0

2 years ago

Read 2 more answers

I’m kinda confused. Can someone help.

horsena [70]

Answer:

PQ = $PM\cos MPQ + MQ\cos MQP=2PM\cos MQP$

Step-by-step explanation:

given MQR = 60, PQR = 75

MQP = 75 -60= 15 $QR = ((18(1+\cos 30))^{2}-(2\cos 15)^{2})^{\frac{1}{2}}$

WE KNOW THAT MQR +QRM +QMR = 180

MPQ = MQP AS ANGLE OPPOSITE TO EQUAL SIDES ARE EQUAL

THEREFORE QMR = 90 - 60 = 30

therefore PQM = 75 - 60 = 15

PM = PQ because M is the mid point

therefore PR = PM + $MQ\cos QMR$

PR = $18(1+\cos 30)$

$QR = (PR^{2}-PQ^{2}))^{\frac{1}{2}}$

PQ = $PM\cos MPQ + MQ\cos MQP=2PM\cos MQP$

5 0

3 years ago

Pls help I’ll make brainlest and give extra points

allochka39001 [22]

Answer:

p>-3 open circle going to the right

$m\leq -4$ closed circle going to the left

n<5 open circle going to the left

$h\geq 2$ closed circle going to the right

1>x open circle going to the left

-1=d just a closed circle

Step-by-step explanation:

Before I answer these here are some good notes

If the inequality sign is < or > then the circle is going to be open

If the inequality sign is $\leq or\geq$ then the circle is going to be closed

If the inequality sign is facing the variable (ex: x>3) then the line is going to be going to the right

If the inequality sign is facing the constant (ex: x<3) then the line is going to be going to the left

p>-3 open circle going to the right

$m\leq -4$ closed circle going to the left

n<5 open circle going to the left

$h\geq 2$ closed circle going to the right

1>x open circle going to the left

-1=d just a closed circle

6 0

2 years ago

Solve the following proportion for u.<br> 5/8=u/9<br> Round the answer to the nearest tenth.

Firlakuza [10]

Answer:

5/10=u/9

explain answer: so to get this answer 5x8=40 so like the closes number to eight will be 9 and 10 but they said closes 10 so it will be 5/10 and =u/9 so answer= 5/10=u/9

4 0

2 years ago

Could someone help me with this ASAP? thanks !

Maru [420]

<h3>Answer:</h3>

A. $6x^2$ +-5x+14x+-35

$6x^2$ +9x-35

B. $5x^4+-3x^3+10x^3+-6x^2$

$5x^4+7x^3-6x^2$

C. $25x^2+-20x+20x+-16$

$25x^2-16$

D. $x^4+-4x^2+-7x^2+28$

$x^4-11x^2+28$

$====================================$

Step-by-step explanation:

A. (3x*2x)+(3x*-5)+(7*2x)+(7*-5)

Multiply and simplify.

$6x^2$ +9x-35

B. ( $x^2*5x^2$ )+( $x^2*$ -3x)+(2x $*5x^2$ )+(2x $*-3x$ )

Multiply and simplify.

$5x^4+7x^3-6x^2$

C. $(5x*5x)+(5x*-4)+(4*5x)+(4*-4)$

Multiply and simplify.

$25x^2-16$

D. $(x^2*x^2)+(x^2*-4)+(-7*x^2)+(-7*-4)$

Multiply and simplify.

$x^4-11x^2+28$

I hope this helps!

But you should really do this yourself.

3 0

3 years ago