What is the area? PLEASE HELP

Mathematics

2 answers:

mylen [45]3 years ago

7 0

Answer:

14mm×20mm=280mm²

14mm×12mm/2=84mm²

3.14×10²mm=314mm²

280m²+84mm²+314mm²=678mm²

Shalnov [3]3 years ago

7 0

Answer:

521mm^2

Step-by-step explanation:

First, separate the shapes.

-Half circle= diameter of 20, radius 10

-Rectangle= 14x20

-Triangle= (32-20)x14= 12x14

Then, calculate

Circle equation= (pi)r^2= (pi)(10)^2= 314.16 -> divide by 2 for half circle= 157.1

Rectangle= 14x20=280

Triangle= (12x14)=168 -> Divide by two because it's a triangle= 84

Add 157 + 280 + 84 and you get 521

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================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$