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zepelin [54]
2 years ago
14

Help me please thank you

Mathematics
2 answers:
RUDIKE [14]2 years ago
7 0
Agree with first person

59.60 - 4.80 = 54.80, total cost of CDs without tax

54.80/4 = 13.70, cost per colliervilledragons.org
LuckyWell [14K]2 years ago
3 0

Answer:

$13.70

Step-by-step explanation:

$59.60 - $4.80 = $54.80

$54.80 / 4 = $13.70

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Please help. will mark brainliest if its right.180-x=3(90-x)
DerKrebs [107]
<h2>hope it helps you please mark me as brainliest </h2>

4 0
3 years ago
Which is an exponential growth function f(x)=6(0.25)x<br> f(x)=0.25(5.25)x
Vikki [24]

Answer: Second Option

f(x)=0.25(5.25)^x

Step-by-step explanation:

The exponential growth functions have the following form:

f(x) = a(b)^x

Where a is the main coefficient, b is the base and x is the exponent.

For this type of functions the base b must always be greater than 1. Otherwise it would be an exponential decay function

Among the options given, the only function whose base is greater than 1 is the second option:

f(x)=0.25(5.25)^x

6 0
3 years ago
Read 2 more answers
NEED HELP A triangle is cut from a rectangle. The height of the triangle is half of the unknown side length s. The area of the s
Nesterboy [21]

Answer: 14s - 7s/2 = 84

Step-by-step explanation:

Given that s is the length of the unknown side:

Area of the shaded region = 84

Area of rectangle - Area of triangle = 84

Area of rectangle = L * W

= 14 * s

= 14s

Area of triangle = ¹/₂ * base * height

= ¹/₂ * 14 * s/2

= 7s/2

Area of shaded region:

14s - 7s/2 = 84

Solving for s:

14s - 7s/2 = 84

28s - 7s = 168

21s = 168

s = 168/21

s = 8 inches

4 0
2 years ago
Which is more 0.5 or 5.0 and which is more 0.5 or 0.50
andriy [413]
1) 5.0
2) same

Hope that helped
And number two is equal because the 0 on the end don't count.
You could ask an teacher if you want, I mean I don't mine
7 0
3 years ago
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If in fact 15% of the items in shipment are defective, what is the probability of at least 2 defectives in the sample
Mashcka [7]
Posibility it is 20%
3 0
3 years ago
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