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2 years ago

5

three swimmers competed in the 50 M Freestyle race I description of their swimmi speed is given order the swimmers on the first

to third place

2 answers:

kkurt [141]2 years ago

5 0

Terrance, Mike, Nathan. Terrance must be greater than Mike, and Mike covers the same amount of distance in less time than Nathan.

Delicious77 [7]2 years ago

3 0

Answer: terrance mike then nathan

Step-by-step explanation:

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5. Which of the following is not shown in the

soldi70 [24.7K]

C.
(I’m pretty sure but if I’m wrong I apologize in advance)

8 0

2 years ago

your quidditch league has 5 teams. you will play a tournament next week in which every team will play every other team once. eac

Airida [17]

The fewest number of days over which the tournament can take place is 5 days.

<h3>How to calculate the number of days?</h3>

As each team plays with other team Once and we have total 5 teams so number of matches will be (4+3+2+1)

Counted as team 1 plays with all other teams = 4 matches

Team 2 plays with team 3,4,5 =3 matches

Team 3 play with team 4,5=2 match

And the last match is between team 4 and team5

Total match = 10 and can be played two matches per day:

Number of days = 10/2

= 5 days.

Learn more about expressions on:

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8 0

9 months ago

Find the inverse of f(x)=1/(x^3)

Pepsi [2]

Answer:

Step-by-step explanation:

y $f(x)^{-1} = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}$

4 0

2 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

2 years ago

Two numbers have a sum of 9 when added together.

antiseptic1488 [7]

Answer:40

Step-by-step explanation:+$)#)#

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2 years ago