I=$52,000
R=6.75%
T=5.5 years
P=$19,305
Answer:
D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.
Step-by-step explanation:
In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.
So it would appear as s ≥ 3g.
If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.
60 ≥ 3(20)
60 ≥ 60. These numbers make the linear system true.
If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥ 3g and plug in each variable from the answer choices until you find the variables that make the linear system true.
Answer:
15 shirts in one hour
Step-by-step explanation:
there are 60 minutes in an hour, 20 times 3 is 60, 5 times 3 is 15
Answer:
7 f(t)
Step-by-step explanation:
So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.
w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.
As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:
w(r) = w[7f(t)]
So, we represented the liters in one week by it measure of days.
So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:
w (r) = w[7 f(t)] = 7 f(t)
Here we hace the w function represented in terms of t instead of r.
Step-by-step explanation:
