Answer:
The workers will need 10 days to finish the job.
Step-by-step explanation:
To solve this question we can use a compound rule of three. We have:
10 road workers -> 5 days -> 2h/day
2 road workers -> x days -> 5h/days
The first thing we should do is analyze how the proportions between the variables work, if they're inversely or directly proportional. If we raise the number of workers we expect that the amount of days needed to finish the job lowers and if we raise the number of hours worked in a day we expect that the workers would need less days to finish the job. So we need to invert the fractions that are inversely proportional to the amount of days worked, then we have:
2 -> 5 -> 5
10-> x -> 2
x = (5*2*10)/(2*5) = 100/10 = 10 days
If you continue the top ray down to the lower our the two lines you create an angle that it's an exterior angle of a triangle and it's also a corresponding angle to the 110° angle. since corresponding angles are congruent this angles is also 110°. this angle makes a linear pair with the angle to it left, the lower right angle on the triangle. linear pairs add to 180° so the angle has to be 70°. the lower left angle of this triangle is given as 37°. since the 3 angles of a triangle must add to 180° , the top angle has to be 180-(70+37)=73. since the top angle of the triangle makes a linear pair with the angle in question, our angle has to be 180-73=107°
Answer:
120° CW or 240° CCW
Step-by-step explanation:
Segment GO makes a 120° angle with segment PO, so the minimal rotation is 120° CW to move PQ to GH. Often rotation angles are measured CCW when direction is not specified. Hence the rotation angle would be 240° (CCW).
Answer:
5.43333 recurring
Step-by-step explanation: Mean is the average of a set of numbers. That is, the sum of the digits in the set, divided by the number of the digits.
In the question above, we have 9 digits. So we find the sum of the digits divided by 9.
(9.6+2+4.1+8+5.9+2+3.7+6+7.6)/9
48.9/9
5.4333recurring
hope this helped!
Answer:
MBI, MBV, ABV, ABI, MPI, MPV, APV, API