Answer:
d. The cell begins to elongate and the two poles have an equivalent collection of chromosomes.
Explanation:
The cell cycle is a fundamental cellular process by which a parent cell divides into two or more daughter cells. In somatic cells, this cycle can be divided into two major phases: interphase, where the cell prepares for its division, and mitosis or 'M phase'. The M phase can in turn be divided into four stages: 1-prophase (also divided into early prophase and prometaphase), 2-metaphase, 3-anaphase, and 4-telophase. During prophase, chromatin condenses, thereby forming visible chromosomes. Subsequently, during metaphase, the sister chromatids (i.e., the two identical halves of a single replicated chromosome) align along the middle of the cell at the metaphase plate by attaching their centromeres to the spindle fibers. Next, during anaphase, sister chromatids are separated and move to opposite poles of the cell, pulled by the mitotic spindle fibers. At the end of anaphase, the microtubules of the mitotic spindle pull the two sister chromatids toward opposite poles, thereby the cell gets begins to lengthen. Finally, during the telophase, daughter chromosomes arrive at opposite poles and uncoil, while daughter nuclei begin to form at the two poles and nuclear envelopes are formed.
What’s the question though?
It is a rare genetic mutation that both the maternal and paternal partners have to be at least a carrier for the albinism gene.
Answer:
<u><em>Fatty acid degradation produces acetyl-CoA</em></u>
<em>When carbohydrate concentrations drop, any available oxaloacetate is diverted to</em><em><u> gluconeogenesis to produce the glucose </u></em><em>necessary for red blood cell and brain function. If acetyl-CoA cannot enter the citric acid cycle (and acetyl-CoA cannot be converted to pyruvate in mammals), it is converted to ketone bodies.</em>
