Since both values are positive, it is in quadrant 1
Answer:
in picture
Step-by-step explanation:
Attention:THIS IS PART B <em>ONLY!</em>
First,find the unit rate.
35/2 and <em>x</em>/1
35 divided by 2 = 17.5 so the unit rate for J.K. is 17.5 pages per hour.
now,R.L.
45/3 and <em>x</em>/1
45 divided by 3 = 15 so the unit rate for R.L. is 15 pages per hour
now we need to divide 355 by 17.5 and divide it by 15.Whichever quotient is smaller,finishes the book first
355 divided by 17.5 = about 20 hrs----J.K.
355 divided by 15 = about 24 hrs-----R.L.
So,who read faster?
Answer:
a) 0.283 or 28.3%
b) 0.130 or 13%
c) 0.4 or 40%
d) 30.6 mm
Step-by-step explanation:
z-score of a single left atrial diameter value of healthy children can be calculated as:
z=
where
- X is the left atrial diameter value we are looking for its z-score
- M is the mean left atrial diameter of healthy children (26.7 mm)
- s is the standard deviation (4.7 mm)
Then
a) proportion of healthy children who have left atrial diameters less than 24 mm
=P(z<z*) where z* is the z-score of 24 mm
z*=
≈ −0.574
And P(z<−0.574)=0.283
b) proportion of healthy children who have left atrial diameters greater than 32 mm
= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm
z*=
≈ 1.128
1-P(z<1.128)=0.8703=0.130
c) proportion of healthy children have left atrial diameters between 25 and 30 mm
=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm
z(30)=
≈ 0.702
z(25)=
≈ −0.362
P(z<0.702)=0.7587
P(z<−0.362)=0.3587
Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4
d) to find the value for which only about 20% have a larger left atrial diameter, we assume
P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.
Then P(z<z*)=0.8 and z*=0.84. That is
0.84=
solving this equation for X we get X=30.648