Answer:
It is the tenths place. 109.7 is greater than 109.6
Following transformations on Triangle ABC will result in the Triangle A'B'C'
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
In Triangle ABC, the coordinates of the vertices are:
A (1,9)
B (3, 12)
C (4, 4)
In Triangle A'B'C, the coordinates of the vertices are:
A' (3, -3)
B' (5, -6)
C' (6, 2)
First consider point A of Triangle ABC.
Coordinate of A are (1, 9). If we reflect it across x-axis the coordinate of new point will be (1, -9). Moving it 2 units to right will result in the point (3, -9). Moving it 6 units up will result in the point (3,-3) which are the coordinates of point A'.
Coordinates of B are (3,12). Reflecting it across x-axis, we get the new point (3, -12). Moving 2 units towards right, the point is translated to (5, -12). Moving 6 units up we get the point (5, -6), which are the coordinate of B'.
The same way C is translated to C'.
Thus the set of transformations applied on ABC to get A'B'C' are:
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
I think it would be the last one from my calculations im not positive but its what makes sense.
We know, Volume of a Cube = Edge³
so, it would be: f(v) = a³
Hope this helps!
Answer:
The distance cover by Bell is 8 miles .
Step-by-step explanation:
Given as :
The distance cover by Mike = The distance cover by Pete = D miles
Let The distance cover by Bell = d miles
The distance cover by Mike = 15 miles + distance cover by Bell
i.e D = 15 + d ............1
Again
The distance cover by Pete = three time distance cover by Bell - 1 miles
i.e D = 3 × B - 1
Or, D = 3 d - 1 ............2
Now, Solving equation 1 and 2
So, 15 + d = 3 d - 1
Or, 3 d - d = 15 + 1
Or, 2 d = 16
∴ d = 
i.e d = 8 miles
So,The distance cover by Bell = d = 8 miles
Hence, The distance cover by Bell is 8 miles . Answer
