Step-by-step explanation:
x in (-oo:+oo)
1/7-(3*((3/7)*x-(2/7))) = 0
1/7-3*((3/7)*x-2/7) = 0
1/7-3*(3/7*x-2/7) = 0
(-3*7*(3/7*x-2/7))/7+1/7 = 0
1-3*7*(3/7*x-2/7) = 0
7-9*x = 0
(7-9*x)/7 = 0
(7-9*x)/7 = 0 // * 7
7-9*x = 0
7-9*x = 0 // - 7
-9*x = -7 // : -9
x = -7/(-9)
x = 7/9
x = 7/9
U= 9.4m/s
v= -7.4m/s (Negative sign because it is in the opposite direction as he is rolling back)
t= ?
s= ?
a= ?
Now, a= v-u/t
= -7.4-9.4÷3
=-5.6
By the second equation of motion.
s= ut+1÷2at*2 ( *2 is the power)
s= 9.4×3+1÷2×-5.6×3*2
= 28.2 +(-25.2)
=3
Therefore s or the distance travelled is 3m.
Y-4=2/-3(x-6) I believe that’s the answer hope this helped
