180-110=70
180-(70+59)=180-129=51
Z=51 im p sure
Answer:
$712.
Step-by-step explanation:
We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.
We will use compound interest formula to solve our given problem.
, where,
A = Final amount,
P = Principal amount,
r = Annual interest rate in decimal form,
n = Number of times interest is compounded per year,
t = Time in years.

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.







Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.
Well first off here we know that one of the figures here is 24 and the other one is 18 so immediatly we can make a fraction out of this by putting the bigger number on the bottom as the denominator and the smaller number on the top as the numerator like so 18/24 we also know that this fraction can easily be simplified like so 3/4 (because 6 goes into each of them evenly) so the scale factor of these 2 figures is 3/4 or C.Enjoy!=)
I think to N because it make more sense in the number line
Answer:
5,9,2
Step-by-step explanation: