WILL GIVE BRAINLIEST

Eight angles of a nonagon measure 1389, 154º. 145°, 132°, 148°, 143,

PIT_PIT [208]

Answer:

103°

Step-by-step explanation:

The total angle in a nonagon is 1260. To get the missing angle, we add up all the given angle together and subtract it from 1260.

138 + 154º + 145° + 132° + 148° + 143 + 147 + 150 = 1157

1260 - 1157 = 103

Therefore, the missing angle is 103°

6 0

3 years ago

What is the answer of these, how do you do these

Charra [1.4K]

1 is perpendicular bc it's the opposite reciprocal so Basically it's the original fraction upside down. 2 is parallel bc both fractions have the same slope but one is negative

3 0

4 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

so

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

so

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago

What is -138 divided by 18

balu736 [363]

-138/18= -7.6 repeating

4 0

3 years ago

Read 2 more answers

Question 22 A city has a population of people. Suppose that each year the population grows by . What will the population be afte

Alexeev081 [22]

Answer:

911,690.

Step-by-step explanation:

Please consider the complete question.

A city has a population of 390,000 people. Suppose that each year the population grows by 6.75%. What will the population be after 13 years? Round your answer the nearest whole number.

We will use exponential growth formula to solve our given problem.

$y=a\cdot (1+r)^x$ , where,