<span>1.
</span>Improve quality of care and reduce health disparities.
<span>2.
</span>Read the orders in the medical record and make
sure to read it back again to verify accuracy.
<span>3.
</span>Maintain the security and privacy of patient
health information.
<span>4.
</span>Talk to the patients and families in management of
their health care.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
This question is about what is a good analogy for explaining the actions of a compiler? The correct option is <u> automatic programming of kitchen devices
.</u>
<u>
</u>
a hybrid ability of a car to use multiple energy sources (false)
this analogy is not correctly mapped on the compiler, becuase the compiler can be designed only for one type of language, for example, the program that calculates the average of students number can be easily programmed in C++ and in C#. But you cannot compile the C# program in C++ compiler and vice versa.
a street map of a local subdivision (false)
Because you can design a compiler for a not specific subdivision of programming.
an interpreter who speaks several languages
it is not an analogy, however, an interpreter can handle only one type of language.
an automatic programming of kitchen devices (true)
This is a good analogy of compiler because you give input to the device and that device based on your input gives you back an output. Similarly, you give input to the compiler in form of language syntax, and it automatically give you output based on your input.
Answer:
sentence = "hello wow a stores good"
same_letter_count = 0
sentence_list = sentence.split()
for s in sentence_list:
if s[0] == s[-1]:
same_letter_count += 1
print(same_letter_count)
Explanation:
*The code is in Python.
Initialize the sentence with a string
Initialize the same_letter_count as 0
Split the sentence using split method and set it to the sentence_list
Create a for loop that iterates through the sentence_list. If the first and last of the letters of a string are same, increment the same_letter_count by 1
When the loop is done, print the same_letter_count
