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tino4ka555 [31]
3 years ago
10

There are 4 green marbles and 7 silver marbles in a bag. You randomly choose one of the marbles. What is the probability of choo

sing a green marble?
7/11
4/11
4/7
7/4
Mathematics
2 answers:
Alecsey [184]3 years ago
8 0

Answer:

B.

Step-by-step explanation:

First, you will need to find out how many marbles there are total, which is 11. After doing so, you are able to eliminate two of your answer choices already (C. and D.). Next, identify how many green marbles are in there, which is 4. You are able to identify that A. can be eliminated as well. With you finding probability, the total amount will be on the bottom. So, you can see that there is a 4/11 or about 36% chance that a green marble will be picked.

Hope this helps! :)

Aliun [14]3 years ago
5 0

Answer:

4/11

Step-by-step explanation:

there are 4 green out of 11 total

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lbvjy [14]
200 - [ ( 50 - 4 ) × 3 + 5 ]
= 200 - [ 46 × 3 + 5 ]
<Put brackets around the 2 number that enclose the times sign as a reminder to do that first>
= 200 - [ ( 46 × 3 ) + 5 ]
= 200 - [ 138 + 5 ]
= 200 - (143)
= 57

Hope this helps!
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3 years ago
The last time Reid checked, his dog weighed 30 kilograms. Reid just measured his dog again and found out that it weighs 10% less
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10. A taco stand sells tacos for $3.25 each. The stand’s expenses for the day are $210. Define your variables and write an inequ
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8 0
3 years ago
Please I need answers Factorize x²-6x+9
miskamm [114]

Answer:

The factors of the given equation are:

x^2-6x+9=(x-3)(x-3)=(x-3)^2

Step-by-step explanation:

We have :

x^2-6x+9

Using middle term splitting theorem to factorize the expression :

x^2-3x-3x+9

x(x-3)+(-3)(x-3)

(x-3)(x-3)

x^2-6x+9=(x-3)(x-3)=(x-3)^2

The factors of the given equation are:

x^2-6x+9=(x-3)(x-3)=(x-3)^2

4 0
3 years ago
Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the given curves
Vadim26 [7]

The expression on the left side describes a parabola. Factorize it to determine where it crosses the y-axis (i.e. the line x = 0) :

-3y² + 9y - 6 = -3 (y² - 3y + 2)

… = -3 (y - 1) (y - 2) = 0

⇒   y = 1   or   y = 2

Also, complete the square to determine the vertex of the parabola:

-3y² + 9y - 6 = -3 (y² - 3y) - 6

… = -3 (y² - 3y + 9/4 - 9/4) - 6

… = -3 (y² - 2•3/2 y + (3/2)²) + 27/4 - 6

… = -3 (y - 3/2)² + 3/4

⇒   vertex at (x, y) = (3/4, 3/2)

I've attached a sketch of the curve along with one of the shells that make up the solid. For some value of x in the interval 0 ≤ x ≤ 3/4, each cylindrical shell has

radius = x

height = y⁺ - y⁻

where y⁺ refers to the half of the parabola above the line y = 3/2, and y⁻ is the lower half. These halves are functions of x that we obtain from its equation by solving for y :

x = -3y² + 9y - 6

x = -3 (y - 3/2)² + 3/4

x - 3/4 = -3 (y - 3/2)²

-x/3 + 1/4 = (y -  3/2)²

± √(1/4 - x/3) = y - 3/2

y = 3/2 ± √(1/4 - x/3)

y⁺ and y⁻ are the solutions with the positive and negative square roots, respectively, so each shell has height

(3/2 + √(1/4 - x/3)) - (3/2 - √(1/4 - x/3)) = 2 √(1/4 - x/3)

Now set up the integral and compute the volume.

\displaystyle 2\pi \int_{x=0}^{x=3/4} 2x \sqrt{\frac14 - \frac x3} \, dx

Substitute u = 1/4 - x/3, so x = 3/4 - 3u and dx = -3 du.

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\displaystyle -12\pi \int_{u=1/4}^{u=0} \left(\frac34 - 3u\right) \sqrt{u} \, du

\displaystyle 12\pi \int_{u=0}^{u=1/4} \left(\frac34 u^{1/2} - 3u^{3/2}\right)  \, du

\displaystyle 12\pi \left(\frac34\cdot\frac23 u^{3/2} - 3\cdot\frac25u^{5/2}\right)  \bigg|_{u=0}^{u=1/4}

\displaystyle 12\pi \left(\frac12 u^{3/2} - \frac65u^{5/2}\right)  \bigg|_{u=0}^{u=1/4}

\displaystyle 12\pi \left(\frac12 \left(\frac14\right)^{3/2} - \frac65\left(\frac14\right)^{5/2}\right) - 12\pi (0 - 0)

\displaystyle 12\pi \left(\frac1{16} - \frac3{80}\right) = \frac{12\pi}{40} = \boxed{\frac{3\pi}{10}}

6 0
2 years ago
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