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anzhelika [568]
3 years ago
6

What fraction is 4 hours of a day45 mins of an hour240cm3 of a litre​

Mathematics
1 answer:
lesya [120]3 years ago
8 0

4 hours of a day

1/6

45 mins of an hour

3/4

240cm3 of a litre​liter

240cm3=0.24l

6/25

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(BRAINLIEST) and more in the description.
Eddi Din [679]

Step-by-step explanation:

If there are 20 yellow marbles,

there must be 32 - 20 = 12 red marbles.

P(Red marble)

= 12/32

= 0.375.

7 0
3 years ago
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Can someone please help me
Vlada [557]
>>>1/5 is the answer<<<
8 0
3 years ago
At the beginning of an environmental study, a forest covered an area of 1500km^2. Since then, the area has decreased by 6.3% eac
geniusboy [140]

The <em><u>correct answer</u></em> is:

y=1500(0.937)^t

Explanation:

An exponential function is of the form

y=a\times b^x, where a is the initial population, b is 1 plus the amount of yearly change, and x is the number of years.

For our problem, a, the initial population, is 1500.

The yearly change is 6.3%; 6.3% = 6.3/100 = 0.063.  Since it is decreasing, this is negative; 1+(-0.063) = 0.937.

We use t as the number of years.

This gives us

y=1500(0.937)^t

3 0
3 years ago
Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among
Olegator [25]

Answer:

a) X[bar]₁=  1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

a)

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

b)

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

c)

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= \frac{1}{n_1-1}[∑X₁² - (( ∑X₁)²/n₁)]= \frac{1}{14} + [52829538 - (\frac{27588^{2} }{15}) = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0
3 years ago
A city known for its temperature extremes started the day at -5 degrees Fahrenheit. The temperature increased by 78 degrees Fahr
charle [14.2K]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Starting temperature = - 5°F

Temperature at midday =increase in temperature by 78°F = (starting temperature + 78°F)

Temperature at nightfall = decrease in temperature by 32°F = ( temperature at midday - 32°F)

Temperature at midday:

(-5°F + 78°F) = 73°F

Temperature at nightfall:

(Temperature at midday - 32°F)

(73°F - 32°F) = 41°F

7 0
3 years ago
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