Given: <span>9=(1/27)^(a+3)
[Note: Please review rules of PEMDAS.
The question posted as is means
</span><span>9=[(1/27)^a]+3 which is probably not what you mean. It has been interpreted with (a+3) as the exponent, please check.]
</span><span>
Need to find value of a that satisfies above.
We will first isolate a in order to solve for its value.
</span>9=(1/27)^(a+3)
Switch unknown to the left
(1/27)^(a+3) = 9
Since both 27 and 9 are powers of 3, we can take log to base 3.
take log (base 3) on both sides, applying rule of logarithm of exponents.
(a+3)log_3(1/27)=log_3(9)
(a+3)log_3(3^(-3))=log_3(3^2)
Apply definition of logarithm [log_a(a^k)=k]
(a+3)(-3)=2
(a+3)=-2/3
a=-3 2/3=-11/3
Check: (1/27)^(-11/3+3)=(1/27)^(-2/3)=(3^(-3))^(-2/3)=3^(-3(-2/3))=3^2=9 ok
Answer: a=-11/3 or a=-3.667 (approx.)
Answer:
It is Associative property :))
Step-by-step explanation:
Answer:
x-value is 4
Step-by-step explanation:
2x-3y=-1
3x+4y=24
We can solve the equation by eliminating y
We multiply the first equation by 4 and the second by 3
4(2x-3y=-1 )
3(3x+4y=24)
8x -12y = -4
9x +12y = 72
Then we add the two equations;
8x -12y = -4
9x +12y = 72
17x = 68
x = 4
Thus the x-value is 4
Answer:
a.
b.
c.
e.
Step-by-step explanation:
all are equivalent
Answer:
1: 3/4
2: 1080
Step-by-step explanation:
I hope this is right and helps you out!
