The z-score is given by the formula:
z=(x-μ)/σ
μ=1252
σ=129
The answer to the questions given will be as follows:
a] <span>what is the probability that a randomly selected bag contains between 1100 and 1400 chocolate chips?
z=(1400-1252)/129
z=1.15625
P(x</span>≤<span>1400)=0.8770
z=(1100-1252)/129
z=0.1190
P(X</span>≤1100<span>)=0.1190
the answer will be:
P(1100</span>≤x≤1400<span>)=0.8770-0.1190=0.758
b]</span><span>what is the probability that a randomly selected bag contains fewer than 1000 chocolate chips?
</span>z=(1000-1252)/129=-1.954
P(X≤1000)=0.0256
c] <span>what proportion of bags contains more than 1200 chocolate chips?
z=(1200-1252)/129
z=-0.4031
P(X</span>≥1200<span>)=1-P(X</span>≤1200<span>)=1-0.4031=0.5969
</span>
Since all the variables cancel out and the coefficient equal to eachother, this system of equation has
<u>infinitely many solutions!</u>
They can be different because Daryl is doing it online so he will not have to swing arcs on the computer screen he will just use circles. Hope that this helps!
∪⊂⊃⊆⊇∩
Answer:
10
Step-by-step explanation:
I assume it's a rectangle, therefore:
P = 50
a = 15 ft
b = ?
P = 2a + 2b
50 = 2 * 15 + 2b
50 = 30 + 2b
2b = 50 - 30
2b = 20
b = 10
Answer:
incomplete
Step-by-step explanation:
please send the full information, I can't see students belonging to acers
