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den301095 [7]
3 years ago
6

• 2 * 3 = 153 * 4 = 284 * 5 = 45Then, 6 * 2 = _______​

Mathematics
1 answer:
olga_2 [115]3 years ago
6 0

Answer:

16?

Step-by-step explanation:

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Helpp picture above I will mark
ivolga24 [154]

Answer:

I believe the answer is 45

Step-by-step explanation:

First do the parentheses: 12-2=10

Then do the exponent: 3^2=3*3=9

Next multiply 9 by 10: 9*10=90

Lastly divide 90 by 2: 90/2=45

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3 years ago
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-2x+10y=25<br> X-25y=3<br><br> Elimination method
Mrac [35]

Answer:

equation form: x=-131/8y -31/40

Step-by-step explanation:

this is addition/elimination

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3 years ago
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HELP PLEASE! THIS IS MY LAST QUESTION ILL GIVE BRAINLIEST, NO LINKS. &lt;3
Elena L [17]

Answer: C {3, 4}

Step-by-step explanation:

<em>Solve the inequality:</em>

7x + 6 > 20

7x > 20 - 6

7x > 14

x > 2

Only 3 and 4 are greater than 2.

7 0
3 years ago
To the nearest hundredth, what is the length of line segment AB?
agasfer [191]
I would say the answer is 8.25
3 0
3 years ago
A report indicated that 37% of adults had received a bogus email intended to steal personal information. Suppose a random sample
fiasKO [112]

Answer:

5.05% probability that no more than 34% had received such an email.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 700, p = 0.37

\mu = E(X) = np = 700*0.37 = 259

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{700*0.37*0.63} = 12.77

In a random sample of 700 adults, what is the probability that no more than 34% had received such an email?

34% is 0.34*700 = 238

So this probability is the pvalue of Z when X = 238.

Z = \frac{X - \mu}{\sigma}

Z = \frac{238 - 259}{12.77}

Z = -1.64

Z = -1.64 has a pvalue of 0.0505

5.05% probability that no more than 34% had received such an email.

7 0
4 years ago
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