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3 years ago

Please Help me, im not smart ✨

Mathematics

2 answers:

Rufina [12.5K]3 years ago

8 0

Answer:

8: 9 and 6

9: -8 and -4

10: i'm not sure

Anika [276]3 years ago

6 0

Answer:

-8 and -4

Step-by-step explanation:

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A particle moves along the x-axis with position function s(t) = ecos(x). How many times in the interval [0, 2π] is the velocity

Ede4ka [16]

Answer:

It goes to zero three times

Step-by-step explanation:

s(t) = e^ cos(x)

To find the velocity, we have to take the derivative of the position

ds/dt = -sin x e^ cos x dx/dt

Now we need to find when this is equal to 0

0 = -sin x e^ cos x

Using the zero product property

-sin x=0 e^cos x= 0

sin x = 0

Taking the arcsin of each side

arcsin sinx= arcsin 0

x = 0 ,pi, 2 pi

e^cos x= 0

Never goes to zero

6 0

3 years ago

Read 2 more answers

Find the number which replaces the question mark

Sati [7]

I think it would be 40?

8 0

2 years ago

Find the slope of the line that passes through (10, 8) and (9, 13)

7nadin3 [17]

Slope is 5!

Equation:
13-8/9-10=5/1

y2-y1=x2-x1

3 0

3 years ago

How can I find each quotient useing addition

LekaFEV [45]

A quotient can only be figured out by division. Hope this helps!

7 0

4 years ago

A town has a population of 20000 and grows at 4% every year. How long will it be until the population will reach 39400?

olga55 [171]

Answer:

The population will be 39400 in approximately 17 years

Step-by-step explanation:

The increase in population after t years is given by the formula

$P_t = P_0(1+r)^t$

Here

P_0 is the initial population

r is the growth rate and t is time in years

So far we know,

P_0 = 20000

r = 4%

P_t = 39400

Putting the values in the formula

$39400 = 20000(1+0.04)^t\\39400 =20000(1.04)^t\\\frac{39400}{20000} = (1.04)^t\\1.97 = (1.04)^t$

Taking natural log on both sides

$ln |(1.04)^t| = ln |1.97|\\t\ ln\ |1.04| = ln\ |1.97|\\t = \frac{ln\ 1.97}{ln\ 1.04}\\t = 17.287\\t \approx 17$

Hence,

The population will be 39400 in approximately 17 years

8 0

3 years ago

Please Help me, im not smart ✨​

Please Help me, im not smart ✨