Answer: the range for one game is {$0, $2,590,000}
Step-by-step explanation:
The revenue, on average, can be written as:
Y = $35*x
where y is the revenue and x is the number of tickets sold.
The domain of this function is equal to {0, 74000} this means that they can sell any whole number of tickets between 0 and 74000.
To find the range we need to evaluate y in bot extremes of the domain (because we have a linear relation)
minimum revenue
y(0) = $35*0 = $0
maximum revenue
y(74000) = $35*74000 = $2,590,000
So the range for one game is {$0, $2,590,000}
Length is 4
Width is 5
Hope this helps
33
Since it is parallel, that means that the line will have the same slope. Just simplify and add the x values in the first equation to get 33x.
2<3 | *-2
if the sign it is not changed ⇒ -4 < -6 but it is false ( the negative number is bigger when the number after is smaller)
⇒the sign must be changed
- 4 > -6
but in equation the sign remain " ="
⇒ in equation the change does not happen
Ex 3=2+1 | -2
-3*(-2)= - 6 = -2*(2+1)= - 4 - 2 true
Lets find that out writing equations and solving them, a multiple of 1/6 is something like this (1/6)x, so we have
(1/6)x > 3/6
and
<span>(1/6)y < 4/6
</span>lets solve both equations:
<span>(1/6)x > 3/6
</span>x > 6(3/6)
x > 3
<span>(1/6)y < 4/6
</span>y < 6(4/6)
y < 4
So the number must be between 3 and 4, which is obvious, lets try with 3.5 then, that is 3 5/10 or 35/10 = 7/2 in fractional form, and lets try it out:
(1/6)(7/2) = 7/12
finally we compare with the original fractions:
1/6 < 7/12
2/12 < 7/12
So, it comply with being greater than 1/6, now lets compare with 4/6
7/12 < 4/6
<span>7/12 < 8/12
</span>therefore is also smaller than 4/6 and hence 7/12 is a multiple of 1/6 between 3/6 and 4/6
