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Ganezh [65]
2 years ago
15

I conclude from the information given that he is just very lucky. I believe he is lucky, because it is very hard to perform tric

ks or deceive people with a dice. He may be cheating, but a dice can be very unpredictable, and he may just be skilled at the game.
Mathematics
1 answer:
VikaD [51]2 years ago
7 0

Answer:

I believe that the owner of the dice is actually not lucky. There are people who practice throwing dice in a controlled way in order to get a specific side of the dice. If he practices his dice throwing a lot, then he would have a much higher chance of winning at a game of dice.

Step-by-step explanation:

Since you said he was lucky, I decided to make an answer saying that he wasn't lucky so you can choose between both of them. Your answer was good as well.

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A rocket being launched has three engines that are independent of each other. The probability of an engine firing is 0.97. What
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Answer:

.0873

Step-by-step explanation:

3 0
3 years ago
In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
3 years ago
A sequence is defined recursively by the formula f(n + 1) = f(n) + 3 . The first term of the sequence is –4. What is the next te
Jet001 [13]

Answer:

<h2>-1</h2>

Step-by-step explanation:

f(1)=-4\\\\f(n+1)=f(n)+3-\text{the next term is 3 bigger than the previous one}\\\\f(2)=-4+3=-1

8 0
3 years ago
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A car travels at a constant velocity of 84 km/hr. How far would the car travel in 20 minutes?
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d=vt

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3 0
2 years ago
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Answer: Figure QRTS is congruent to figure Q'R'T'S'.

Step-by-step explanation:

A reflection is a rigid motion, and rigid motions preserve congruency.

8 0
2 years ago
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