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Ganezh [65]
2 years ago
15

I conclude from the information given that he is just very lucky. I believe he is lucky, because it is very hard to perform tric

ks or deceive people with a dice. He may be cheating, but a dice can be very unpredictable, and he may just be skilled at the game.
Mathematics
1 answer:
VikaD [51]2 years ago
7 0

Answer:

I believe that the owner of the dice is actually not lucky. There are people who practice throwing dice in a controlled way in order to get a specific side of the dice. If he practices his dice throwing a lot, then he would have a much higher chance of winning at a game of dice.

Step-by-step explanation:

Since you said he was lucky, I decided to make an answer saying that he wasn't lucky so you can choose between both of them. Your answer was good as well.

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Find the slope intercept form of the line passing through (3,9) and (0,3).
ANEK [815]

Answer:

y = 2x +3

Step-by-step explanation:

To find the slope we do (Y1 - Y2)/(X1-X2) aka rise over run

So, m = (9 - 3) / (3 - 0)

m = 2

Now we have y = 2x +b

Notice one of our points is (0,3)

Since the x value of that point is 0, it is the y intercept.

In the slope intercept form b = y-intercept

Therefore b = 3

So, y = 2x + 3

6 0
3 years ago
Suppose a is a positive number and b is a negative num-
nata0808 [166]

Answer:a is positive b is negative

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What does it equal 5/12 + 1\4
baherus [9]
5/12= 2.4
1/4=4
2.4+4=6.4
5 0
3 years ago
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A line has slope
loris [4]
Y = mx+b
-1 = 13/4 (-1) +b
-4/4 + 13/4 = b
9/4 = b
3 0
2 years ago
Write an equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the l
mamaluj [8]

The equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5 is y = \frac{3}{4}x - \frac{5}{4}

<em><u>Solution:</u></em>

<em><u>The slope intercept form is given as:</u></em>

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5

Given line is perpendicular to  − 4 x − 3 y  =  − 5

− 4 x − 3 y  =  − 5

-3y = 4x - 5

3y = -4x + 5

y = \frac{-4x}{3} + \frac{5}{3}

On comparing the above equation with eqn 1, we get,

m = \frac{-4}{3}

We know that product of slope of a line and slope of line perpendicular to it is -1

\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope m = \frac{3}{4}

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}

\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}

y = \frac{3}{4} \times x + \frac{-5}{4}\\\\y = \frac{3}{4}x - \frac{5}{4}

Thus the required equation of line is found

8 0
2 years ago
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