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Diano4ka-milaya [45]
3 years ago
13

P(x) = x^3– 4x^2+ 3x + c

Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:p(x) = x^3– 4x^2+ 3x + c................................

Step-by-step explanation:

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7g:1kg to its simplest form​
hammer [34]

Answer:

7kg:1kg=7:1 itself

Because 7 and 1 has one '1' as a common factor, so they can't be simplified

5 0
4 years ago
Which pair of angles are vertical angles?
Irina-Kira [14]

Answer:

Option 4.∠ERT and ∠MRC

Step-by-step explanation:

Definition of vertical angles  : The angles opposite each other when two lines cross. They are always equal.Vertical" refers to the vertex (where they cross).They are also called vertically opposite angles.

Option 1. ∠KRC and ∠CRH

Refer the figure .

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 2. ∠KRE and ∠ERT

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 3. ∠MRC and ∠KRM

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 4.∠ERT and ∠MRC

MT and EC are the two lines that cross each other at vertex R ,

Thus ∠ERT and ∠MRC are opposite to each other .

Hence ∠ERT and ∠MRC are pair of vertcal angles .



3 0
3 years ago
Read 2 more answers
Elsa drove 603 miles in9 hours at the same rate how many miles would she drive in 7 hours
bezimeni [28]

Answer:

469 miles

Step-by-step explanation:

divide 603 by 9 which is 67, multiply 7 into 67 and the answer into that is 469

hope that helps:)

4 0
3 years ago
For the graph, what is a reasonable constraint so that the function is at least 300?
blsea [12.9K]

Answer:

C) 0 ≤ x ≤ 25

Step-by-step explanation:

We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300

A)x ≥ 0

Refer the graph

At x = 0

f(x)=300

On increasing the value of x , f(x) increases but at x = 12 it starts decreasing

So, x ≥ 0 can also have f(x)<300

So, Option A is wrong

B)−5 ≤ x ≤ 30

At x = -5

f(x) = 100

So, Option B is wrong since we require f(x) is greater or equal to 300

c)0 ≤ x ≤ 25

At x = 0

f(x)=300

At x = 12 , it starts decreasing

At x = 25

f(x)=300

So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25

D)All real numbers

At x = 30

f(x)=0

But we require f(x) greater or equal to 300

Hence Option C is true

8 0
3 years ago
Write 0.83+39 in standard form
SOVA2 [1]
Are u dumb or somthing????????
8 0
4 years ago
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