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Klio2033 [76]
3 years ago
8

What is (-2)(-5)+7 fdsgefgvsefbvgseftbsetbwaesb

Mathematics
1 answer:
klemol [59]3 years ago
4 0

Answer:

17

Step-by-step explanation:

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What is 7/6 ÷ 4 in simplest form
serg [7]
\frac{7}{6} \div 4= \frac{7}{6} \times \frac{1}{4} = \frac{7\times 1}{6\times 4} = \frac{7}{24}

7/24 is your answer :)
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Find the volume of a cone that has a radius of 3 inches and a height of 9 inches. Use 3.14 for pi and round your answer to the n
aalyn [17]

Volume of the cone is 100 in³

Step-by-step explanation:

  • Step 1: Volume of a cone = 1/3 πr²h. Find volume of the cone where r = 3 inches and h = 9 inches.

Volume = 1/3 × 3.14 × 3² × 9

             = 84.78 in³ ≈ 100 in³ (rounding off to nearest hundredth)

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4 years ago
Helpppp y’all sososososo
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3/4

Step-by-step explanation:

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If a zero is <br> , then the graph of its function only touches the x–axis at that zero.
Inga [223]

Answer:

Step-by-step explanation:

Yes. The zeroes of a graph are the values of x where the graph touches (or crosses) the x-axis.

7 0
3 years ago
The loudness, L, of a sound (measured in decibels, dB) is inversely proportional to the square of the distance, d, from
kifflom [539]

Answer:

The jetski is 2.28 dB loud when the person is 41 feet away.

Step-by-step explanation:

Loudness (L) ∝ 1 / Distance² (d²)

Introduce a constant 'K'

L = K (1/d²)

L = K/d²

K = Ld²

Find the K from a previously known information: If a person 8 feet from a jetski hears 60 decibels loud

∴ d = 8 ft , L = 60 db

K = 60(8²) = <em>3840</em>

How loud is the jetski when the person is 41 feet away?

Distance is now 41 ft

since: L = K/d²

∴ L = 3840 / 41²

L = 3840 / 1681

L = 2.28 db

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3 years ago
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