Answer:
It can either be rational or irrational
Step-by-step explanation:
Given the quadratic equation ax²+bx+5 = 0, to get the zeros of the function, we will factorize the function to have;
ax²+bx = -5
x(ax+b) = -5
x = -5 and ax+b = -5
From the second function we have;
ax+b = -5
ax = -5-b
x = -5-b/a
This shows that the other value of x can be rational or irrational depending on the values of a and b
First number is f
Second number is s
f-s=.7
f+s=1
Using elimination, you could solve this.
-1(f-s=.7); eliminate the first number.
-f+s= -.7
f+s=1
2s=.3
s=.15
Now find the second number by plugging it in:
.15+s=1
1-.15=.85
The numbers are .15 and .85.
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ANSWER
B.Yes, f is continuous on [1, 7] and differentiable on (1, 7).

EXPLANATION
The given

The hypotheses are
1. The function is continuous on [1, 7].
2. The function is differentiable on (1, 7).
3. There is a c, such that:


This implies that;




Since the function is continuous on [1, 7] and differentiable on (1, 7) it satisfies the mean value theorem.