Question

Pls help, I've been stuck on this for a week

Answer 1

Answer:

$\sin(C)=\pm\sqrt{1-\cos^2(C)}$

Step-by-step explanation:

Given the Pythagorean Identity:

$\sin^2(C)+\cos^2(C)=1$

We want to solve for sin(C).

First, we will subtract cos²(C) from both sides:

$\sin^2(C)=1-\cos^2(C)$

Next, we will take the square root of both sides. Since we are taking an even-root, we will need to add plus/minus. Hence:

$\sin(C)=\pm\sqrt{1-\cos^2(C)}$