Answer:
3
lazy approach was with a graphic plotting program, but you can also calculate it. with the pq-formula.
p = -6
q = 9
x = -p/2 +- sqrt( (p/2)² - q)
x = -(-6)/2 +- sqrt ( (-6/2)² - 9)
x = 3 +- sqrt(9-9)
x = 3 +- sqrt(0)
x = 3 +- 0
x = 3
The gcf of 15 and 70 is 5
3:5
1:1
1.5 or 1:5 not sure
Answer: Choice B
Range = {-3, 1, 5}
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Explanation:
The domain is the set of all possible input x values. The range is the set of all possible y outputs.
Plug in each x value from the domain, one at a time, to get its corresponding range y value.
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Start with x = -3
f(x) = 2x+3
f(-3) = 2(-3)+3
f(-3) = -6+3
f(-3) = -3
So -3 is in the range.
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Move onto x = -1
f(x) = 2x+3
f(-1) = 2(-1)+3
f(-1) = -2+3
f(-1) = 1
1 is also in the range
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Finally plug in x = 1
f(x) = 2x+3
f(1) = 2(1)+3
f(1) = 2+3
f(1) = 5
The value 5 is the final value in the range.
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All of those values form the set {-3, 1, 5} which is the complete range.
Answer:
y = 4x + 32
Step-by-step explanation:
Given: Temperature at sunrise = 32°F
y is the temperature after x hours of sunrise
Temperature change is 4°F/hour.
The equation of a line in slope intercept form is given by
y = mx +c
where m is the slope, which is the change in value of y to the value of x
and c is the value of y at x = 0
At sunrise, x =0 and y =32
∴ c = 32
Also we see that the change in temperature to that of time is 4/1 = 4
∴ m = 4
Substituting the values of m and c in the equation of line, we have
y = 4x +32
