1. Find the perimeter and area of a rectangle with a length of 3.2 m and a width of 1.5 m.

1 answer:

5 0

<span>1. D) p=9.4 m; A= 4.8 m^2 2. C) 189 ft^2 1. Find the perimeter and area of a rectangle with a length of 3.2 m and a width of 1.5 m. The perimeter of a rectangle is simply twice the sum of it's length and width, so 2(3.2m + 1.5 m) = 2*4.7 = 9.4 m The area of a rectangle is the product of its length and width, so 3.2 m * 1.5 m = 4.8 m^2 Of the available choices, D matches with p=9.4 m; A= 4.8 m^2 2. Find the area of a triangle with a base of 27 feet and a height of 14 feet. The area of a triangle is 1/2 base times height, so 0.5 * 27 ft * 14 ft = 189 ft^2 Of the available choices, C matches with 189 ft^2</span>

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Scientists studying dolphin echolocation simulate the projection of a bottlenose dolphin's clicking sounds using computer

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Step-by-step explanation:

The equation of a parabola with focus at (h, k) and the directrix y = p is given by the following formula:

(y - k)^2 = 4 * f * (x - h)

In this case, the focus is at the origin (0, 0) and the directrix is the line y = -1.3, so the equation representing the cross section of the reflector is:

y^2 = 4 * f * x

= 4 * (-1.3) * x

= -5.2x

The depth of the reflector is the distance from the vertex to the directrix. In this case, the vertex is at the origin, so the depth is simply the distance from the origin to the line y = -1.3. Since the directrix is a horizontal line, this distance is simply the absolute value of the y-coordinate of the line, which is 1.3 inches. Therefore, the depth of the reflector is approximately 1.3 inches.

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1 year ago

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Answer:

The decision is to not reject the null hypothesis.

At a significance level of 0.01, there is not enough evidence to support the claim that the proportion of all those using the drug that experience relief is significantly higher than 50% (P-value = 0.1443).

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that the proportion of all those using the drug that experience relief is significantly higher than 50%.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.5\\\\H_a:\pi>0.5$

The significance level is 0.01.

The sample has a size n=200.

The sample proportion is p=0.54.

$p=X/n=108/200=0.54$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.5*0.5}{200}}\\\\\\ \sigma_p=\sqrt{0.00125}=0.035$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.54-0.5-0.5/200}{0.035}=\dfrac{0.038}{0.035}=1.061$

This test is a right-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z>1.061)=0.1443$

As the P-value (0.1443) is greater than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.01, there is not enough evidence to support the claim that the proportion of all those using the drug that experience relief is significantly higher than 50%.

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4 years ago

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