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boyakko [2]
4 years ago
8

What numbers multiply to 20 & add up to 9.

Mathematics
2 answers:
Fantom [35]4 years ago
5 0

Answer:

4 and 5

Step-by-step explanation:

4 x 5 = 20

4 + 5 = 9

larisa [96]4 years ago
3 0

Answer:

4 and 5

Step-by-step explanation:

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Are (2,9) and (-3,-6) both on the line y = 4x + 6? If not, find an equation for the line that does pass through both points.
igor_vitrenko [27]

Answer:

no, y=3x+3

Step-by-step explanation:

plug both points into the equations:

  • 9=4*2 +6 -> 9=8+6, doesn't work
  • -6=4(-3)+6 -> -6=-6, works

one works but the other doesn't so now we find a line through both points

use the formula (y_2-y_1)/(x_2-x_1) to find the slope:

  • (-6-9)/(-3-2)=-15/-5=3

y=3x+b, plug in a point to find b:

  • 9=3(2)+b
  • 9=6+b
  • b=3
  • y=3x+3
7 0
3 years ago
Circle O has a circumference of 88π cm. What is the length of the radius of the circle? cm
Vitek1552 [10]

Answer:

44cm

Step-by-step explanation:

Formula of circumference of circle: C = 2πr

Since C = 88π

⇒ 88π = 2πr

⇒ r = 88π/2π

⇒ r = 44cm

8 0
3 years ago
To make some draperies, an interior decorator needs 12 1/4 yards of material for the den and 8 1/2 yards for the living room. If
xz_007 [3.2K]

Answer:

1/4 of a yard of material

Step-by-step explanation:

First, we must convert both 12 1/4 yards and 8 1/2 yards to quarters. Since 1/2 of a yard is equal to 2/4 of a yard, 8 1/2 yards will be equal to 8 2/4 yards. 8 yards + 12 yards = 20 yards, and 2/4 of a yard + 1/4 of a yard = 3/4 of a yard, so you get 20 3/4 of a yard to finish the draperies. To find the leftover material, do 21 yards - 20 3/4 yards = 1/4 of a yard of material. Hope this helps!

4 0
3 years ago
Represent each of these relations on {1, 2, 3, 4} with a matrix (with the elements of this set listed in increasing order). a) {
Irina-Kira [14]

Answer:

for a  a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]

Step-by-step explanation:

in matrix, arrays are placed in rows , which represents the horizontal sides from left to right, while arrays in the column are placed vertically from top to bottom. Here, we placed the arrays in a 4x4 matrix

for a  a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]

7 0
4 years ago
Questiom 40 plzzzz answer nd explain?
lesya692 [45]
I am not positive but i think that its the last one.  Any one else???
5 0
3 years ago
Read 2 more answers
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