Tracheoesophageal fistula
Tracheoesophageal fistula (TE) is
a condition in which an abnormal channel (fistula) connects the trachea to the
oesophagus. It is a birth defect and is characterized by extensive salivation
with choking, vomiting and cyanosis during feeding. When eating, food
substances move through abnormal connection and this can cause other illnesses.
From the question given above, Morgan is likely have tracheoesophageal fistula.
A model for a company's revenue from selling a software package is R(p)=-2.5p² + 400p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue.
Answer: p = $80, R = $16,000
Step-by-step explanation:
The maximum is the y-value of the Vertex.
Step 1: Use the Axis-Of-Symmetry (AOS) formula to find x:
x=
R(p) = -2.5p² + 400
a= -2.5 b=400
= 
=80
∴ In order to maximize the value, the company will sell the software package for $80
Step 2: Find the maximum by plugging the p-value (above) into the given equation.
R(80) = -2.5(80)² + 400(80)
= -16,000 + 32,000
= 16,000
Answer:
Option D
Explanation:
Bits of DNA that are interspersed among these repeated sequences are called spacers. Regarding to bacteria, the spacers are taken from viruses that previously attacked the organism. They serve as a bank of memories, which enables bacteria to recognize the viruses and fight against future attacks.
Answer:
A) Proportion of females with the trait is less than 8%
B) Proportion of females that would be carriers is greater than 8%
Explanation:
Only the 8% male sufferers can give their diseased X-chromosome for the female XX to be formed. hence, the proportion of the female carriers is most likely greater than 8%
On the other hand, the proportion of female sufferers will be definitely less than 8%, for 92% of the remaining male population are neither carriers nor sufferers; and the 8% male sufferers are strictly needed to give the disease X-chromosome for a female to have the trait XX.
