Answer:
D. 1.6 yd
Step-by-step explanation:
Use the law of sines.
Answer:
D) q + d = 330
0.25q + 0.1d = 6
Step-by-step explanation:
Let q= numbers of quarters
d = number of dimes
q + d = 33 ...........(1)
q = 33 - d
xq + yd = 6 ..........(2)
We will consider the options to know the correct answer
From option A
q +d = 6
25q + 10d = 33
This is wrong
Option B
q + d = 60
0.25q + 0.1d = 33
This is also wrong
Option C
q+d = 33
25q + 10d = 6
Put q = 33 -d in equation 2
25(33 - d) + 10q = 6
825 - 25d + 10d = 6
825 - 15d = 6
-15d = 6-825
-15d = -819
d = -819/-15
d= 54.6
This is also wrong because d exceeds the combination.
Option D
q+d = 33
0.25q + 0.1d = 6
Put q = 33 -d in equation 2
0.25(33 - d) + 0.1d = 6
8.25 - 0.25d + 0.1d = 6
8.25 - 0.15d = 6
-0.15d = 6 - 8.25
-0.15d = -2.25
d = -2.25/ -0.15
d = 15
q = 33 - 15
q = 18
This is correct
Answer:
The answer to the first one is
D) 2
The answer to the second one is
A) 40
Step-by-step explanation:
If you mark out the points evenly on both sides you are left with 2 in the middle therefore the answer is D) 2
If you add up the number of cyclists that are 26 years or older you get 40.
Answer:
The probability that the ball drawn from the second box is red is 40/99
Step-by-step explanation:
We can divide the event that the second ball drawn is red into 2 disjoint events, and obtain its probability by summing both probabilities for the disjoint cases.
- Case 1: The ball drawn from the first box is red and the ball drawn for the second box is also red
- Case 2: The ball drawn from the first box is green but the ball drawn from the second box is red
For the first case, we have 11 balls in the first box, 7 of them being red. Thus, the probability of drawing a red ball is 7/11. After that, we will put the red ball drawn in the second box, so that it will have 9 balls in total, 4 of them being red. As a consecuence, the probability of drawing a red ball in this instance is 4/9. We need to multiply that probability by the probability that a red ball was drawn first, so we have a probability of 7/11 * 4/9 = 28/99 that the balls drawn are both red.
Now, lets go to the second case. The probability of drawing a green ball from the first box is 4/11, and after placing that ball in the second box, the probability that the new ball drawn is red is 3/9 = 1/3; this is because we will have 3 red balls out of a total of 9 (6 are green). Thus, the probability of this second event is 4/11 * 1/3 = 4/33.
Combining both probabilities, the probability that the ball drawn in the second box is red is 28/99 +4/33 = 40/99 = 0.40404040404...