A rectangle is 10 feet longer than it is wide. The area is 39 square feet. Find the dimensions of the rectangle
1 answer:
Answer:
length = 13 ft
Width = 3 ft
Step-by-step explanation:
Width = w ft
Length = ( w +10 ) ft
Area = 39 square ft
length * width = 39
(w +10)* w = 39
w *w + 10*w = 39
w² + 10w - 39 = 0
w² + 13w - 3w - 3*13 = 0
w(w + 13) - 3(w + 13) = 0
(w + 13) (w - 3) = 0 {Ignore w + 13 , as measurement cannot be in negative}
w - 3 = 0
w = 3
length = 3 +10 = 13 ft
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Answer:
-6, -4
Step-by-step explanation:
Answer:
and
'
The answer 45 and the other one to the question is invalid
Step-by-step explanation:
When x = -2 and y = 3,
10y + 2(3x + 2)
= 10(3) + 2[3(-2) + 2]
= 30 + 2(-4)
= 30 - 8
= 22.
