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ahrayia [7]
3 years ago
12

Computer viruses often spread by means of what?

Computers and Technology
2 answers:
lozanna [386]3 years ago
8 0
Email attachments hope this helps
Alex17521 [72]3 years ago
5 0

Answer:

Email attachments just took the test

Explanation:

Its easy to travel off those because they are free of security and protection ur welcome.

You might be interested in
(The Location class) Design a class named Location for locating a maximal value and its location in a two-dimensional array. The
-Dominant- [34]

Answer:

Here is the Location class:

public class Location {   //class name

   public int row;  // public data field to hold the value of no. of rows

   public int column;  // public data field to hold the value of no. of columns

   public double maxValue;   //public data field to hold the maximum value

   public Location(int row, int column, double maxValue) { //parameterized constructor of Location class

//this keyword is used to refer to a current instance variable and used to avoid naming conflicts between attributes and parameters with the same name

       this.row = row;  

       this.column = column;  

       this.maxValue = maxValue;     }  

   public static Location locateLargest(double[][] a) {   //method that takes a 2 dimensional array a as argument and returns the location of the largest element

       int row = 0;  //initializes row to 0

       int column = 0;  //initializes column to 0

       double maxValue = a[row][column];   //stores largest element

       for (int i = 0; i < a.length; i++) {  //iterates through rows of a[] array

           for (int j = 0; j < a[i].length; j++) {  //iterates through columns of array

               if (maxValue < a[i][j]) {  //if the maxValue is less than the element of 2 dimensional array at ith row and jth column

                   maxValue = a[i][j];  //then set that element to maxValue

                   row = i;  // i is set to traverse through rows

                   column = j;   }             }         }  // i is set to move through columns

       return new Location(row,column,maxValue);     }  } //calls constructor of class by passing row, column and maxValue as argument

Explanation:

Here is the Main class with a main() function to  test program  

import java.util.Scanner;   //to accept input from user

public class Main {   //class name

   public static void main(String[] args) {   //start of main function

       Scanner scan = new Scanner(System.in);  //creates Scanner class object to scan the input from user

 System.out.print("Enter the number of rows and columns in the array: ");  //prompt for user

       int row = scan.nextInt();  // reads value of row from user

       int column = scan.nextInt();  //reads input value of column

       double[][] array = new double[row][column];   //declares a 2 dimensional array named array

       System.out.println("Enter the array:");  //prompts to enter array elements

       for (int i = 0; i < array.length; i++) {  //iterates through the rows of array until the size of array is reaced

           for (int j = 0; j < array[i].length; j++) {  //iterates through the columns of array

               array[i][j] = scan.nextDouble();    }    }   //reads each element at i-th row and j-th column

       Location location = Location.locateLargest(array);  //calls locateLargest method by passing array to it in order to locate the largest element in the array

System.out.println("The largest element in a two-dimensional array is: " + location.maxValue);  //displays the largest element of array

       System.out.println("The location of the largest element is at (" + location.row + ", " + location.column + ")");       }    } //displays the location of the largest element in the two dimensional array

Suppose the user enters 2 rows and 2 columns. The elements are:

1         5.5

4.5      3

The program works as follows:

for (int i = 0; i < array.length; i++) this outer loop iterates through rows

i = 0

inner loop for (int j = 0; j < array[i].length; j++) iterates through columns

array[i][j] = scan.nextDouble(); reads the element at position i-th row and j-th column. This becomes:

array[0][0] = scan.nextDouble();

so element at 0th row and 0th column is 1

Location location = Location.locateLargest(array); now this calls the method which works as follows:

double maxValue = a[row][column]; this becomes:

double maxValue = a[0][0];

so maxValue = 1

for (int i = 0; i < a.length; i++) this loop in method iterates through rows and  for (int j = 0; j < a[i].length; j++) this iterates through columns of array

if (maxValue < a[i][j]) this becomes:

if (maxValue < a[0][0])

As we know that maxValue = 1 so this if condition is true.

                   maxValue = a[i][j];  this becomes:

             maxValue = a[0][0];  

maxValue = 1

Now set row = 0 and column = 0

Now the inner loop value of j is incremented to 1. So j = 1

At next iteration array[0][1] is checked. The element at this position is 5.5

if (maxValue < a[i][j]) is true because 1<5.5 so now value of maxValue becomes:

maxValue = 5.5

and

i = 0  j = 1

This way at each iteration of inner loop the columns are traversed and at each iteration of outer loop rows are traversed.

At next iteration element at array[1][0] is checked which is 4.5. This is not greater than maxValue so maxValue remains 5.5

At next iteration element at array[1][1] is checked which is 3. This is not greater than maxValue so maxValue remains 5.5 .

After both the loops end the statement:

return new Location(row,column,maxValue);

returns row , column and maxValue

where row = 0  column = 1 and maxValue = 5.5

So the output is:

The largest element in a two-dimensional array is: 5.5

The location of the largest element is at (0,1)

3 0
4 years ago
How can i change my age on my profile here bc i am 13 but i accidenlty put 2005 instead of 2006 no need to rush to answer just w
kykrilka [37]

Answer:

Maybe just go to personal settings and try there

Explanation:

3 0
3 years ago
Read 2 more answers
Abby wants to simply share a snapshot of her calendar with another user. Which option should she choose to achieve
lara [203]

Answer:

Screenshot

Explanation:

If what Abby wants is a simple snapshot then her best option would be to take a Screenshot of her calendar. A Screenshot is basically a snapshot/photo of the exact screen that is displayed to you on your personal computer. This is done by pressing the windows key and prtsc key on the keyboard at the same time. The screen will go dark-grey for a second and a snapshot of your screen will be saved in the Windows Pictures folder. She can then grab this picture and send it to whoever she wants.

4 0
3 years ago
What is another name for an unmanaged switch?
Natalka [10]

Answer:

The answer is "Plug and play".

Explanation:

A switch with minimum debugging tools for log-and-play simplicity and also no IP address. The Unmanaged switches are cost-effective and also have limited power, and other choices are not correct, which can be described as follows:

  • Fast Ethernet provides 10 to 100 Mbps speeds, that's why it is not correct.
  • Gigabit provides bandwidth, which is up to 1 Gbps speed, and it is 10 times faster than Ethernet Fast, that's why it is wrong.
  • The trunk provides the link design that's why it is not correct.
7 0
3 years ago
Private void finishMap()
ziro4ka [17]

Answer:

Where can I find Codehs answers?

You can view the solution for an assignment in multiple ways: Through the Assignments page.

...

To view solutions from the Assignments page:

Navigate to the Assignments page.

Click the '...' next to the assignment you wish to view the solution for.

Choose Solution and another page will open with the solution reference.

7 0
3 years ago
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