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3 years ago

How to get the interval?

Mathematics

1 answer:

lukranit [14]3 years ago

5 0

Step-by-step explanation:

Decide on the number of classes.

Determine the range, i.e., the difference between the highest and lowest observations in the data.

Divide range by the number of classes to estimate approximate size of the interval

hope it helps.

<h2>stay safe healthy and happy...</h2>

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PLSS help important (will gibe brainliest)! I dont understand this

bagirrra123 [75]

To form the vector notation for the translation:

--> must find how much the new graph moved horizontally from the old

graph

--> the graph moved 8 units horizontally

--> must find how much the new graph moved vertically from the old

graph

--> the graph moved 4 units vertically

In vector notation, that would be (8,4)

Hope that helps!

7 0

2 years ago

I NEED THIS ANSWER ASAP PLEASE!!!!!! John painted his most famous work in his country, in 1930 on composition board with perimet

mina [271]

Answer:

width=23.205 in.

length=29.085 in.

Step-by-step explanation:

width=x

length =x+5.88

Perimter=x+x+x=5.88+x+5.88=104.58

4x+11.76=104.58

4x=104.58-11.76

4x=92.82

x=23.205

width=x=23.205 In.

length=x+5.88=23.205+5.88=29.085 in.

3 0

4 years ago

A flower garden has been designed with an L-shaped walkway and viewing area around two sides as shown.

nikdorinn [45]

Answer:

c. 2.4 yards

Step-by-step explanation:

If x is the width of the walkway, then the total landscape area is ...

(4.5 +x)(7.5 +x) = 68.31

This quadratic equation can be rearranged to standard form and solved in any of the usual ways.

(x +4.5)(x +7.5) -68.31 = 0

x² +12x -34.56 = 0

Using the quadratic formula, we have ...

x = (-12 ±√(12² -4(1)(-34.56)))/2 = -6 ± √70.56 = -6 ± 8.4

The positive solution is x = 2.4.

The width of the walkway is 2.4 yards.

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A graphing calculator or spreadsheet solver can also find the solution for you.

8 0

3 years ago

Vika [28.1K]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-----------------------------\\\\
\cfrac{s^3}{s^3}\implies \cfrac{216}{1000}\implies \cfrac{\sqrt[3]{216}}{\sqrt[3]{1000}}\implies \cfrac{s}{s}\impliedby \textit{similarity ratio}$

and simplify it away

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3 years ago

How many boards 6in. Long can be cut from a board 2ft long

lions [1.4K]

This is what I got I hope it helps

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3 years ago