Answer:
E. The data is not under the owner’s direct control.
Explanation:
Disadvantages of cloud storage:
- Need for internet connection: We need to accept the fact that the internet connection, whether by broadband, 3G, 4G or 5G. Opening and retrieving data in the cloud becomes impossible without the internet.
- Mistrust: Security breaches are very rare, especially if your content is stored on large enterprise servers that invest heavily in security.
- Internet laws are unclear - and are different in each country: Because servers are scattered around the world, cybercrime is a doubt: in case of a leak, the hacker should be tried according to the virtual laws of the country in which is the server or country of the user who uploaded these files?
- Price: Yes, there are free options, but companies and business owners who create and access large volumes of files may need paid plans to meet their needs.
Answer:
highlight a cell in column A; place your cursor on the border of the cell so it turns into a two sided arrow and drag
Explanation:
y
The answer is D, the standard course of action adopted by a business.
Answer:
I would go with A and B.
Explanation:
The .edu extension means that the information has been verified by educational institutions and most of the time even run by them. This is why it's good to trust sites with the .edu extension.
Similarly, .gov is run by government organizations so not just anyone can upload or edit content. Governments surely fact-check their information before uploading it to their website so they are trustworthy sources.
Answer:
40, 5 and 3
See explaination for the details
Explanation:
A)
Consider the data.
Assume D-cache is empty
An integer size =4bytes
The cache block size =4bytes
Therefore, the number of D-cache misses for reading the first 40 integers is,
= (40×4)/4
= 160/4
= 40
b)
Consider the data.
Assume D-cache is empty
An integer size =4bytes
The cache block size =32bytes
Therefore, the number of D-cache misses for reading the first 40 integers is,
= (40×4)/32
= 160/32
= 5
c)
Consider the data.
Assume D-cache is empty
An integer size =4bytes
The cache block size =64bytes
Therefore, the number of D-cache misses for reading the first 40 integers is,
= (40×4)/64
= 160/64
= 3
