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Y_Kistochka [10]
3 years ago
6

Adriano runs a website that helps writers write better stories. Every month, Adriano receives a subscription fee of $ 5 from eac

h of the subscribers to his website. The website had 200 subscribers last month. This month 40 new members joined the website and 10 members cancelled their subscription.
Mathematics
2 answers:
miv72 [106K]3 years ago
6 0

Answer: the answer is $1150 dollars.

Step-by-step explanation:

ale4655 [162]3 years ago
4 0
So what's the question?
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Which number is represented by the number line
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8,000 of 2ounces how many make 16 ounces
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1,000 I guess I don't really understand the question
HAPPY THANKSGIVING!
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The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of
romanna [79]

Answer: a) \dfrac{3}{874}

b) \dfrac{30}{3059}

c) \dfrac{3575}{12236}

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : 11+13=24

Total number of ways to structure a jury of six people from a group of 24 people :-

^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596

a) Number of ways of selecting a jury of all​ students :-

^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{462}{134596}=\dfrac{3}{874}

b) Number of ways of selecting a jury of all​ faculty :-

^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{1716}{134596}=\dfrac{30}{3059}

c) Number of ways of selecting a jury of two students and four ​faculty :-

^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325

Then , the probability of selecting a jury of all​ students :-

\dfrac{39325}{134596}=\dfrac{3575}{12236}

3 0
3 years ago
after this 120-second period , how much time,in seconds will it take for the scientist to travel back to sea level at the submar
love history [14]
Unanswerable. How bout you give us the appropriate info before asking a question?
4 0
3 years ago
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