Its decagon. cause it has 10 corners.
The quadratic equation that models the height of the rocket after t seconds is:
s(t) = -4.9t² + 39.2t.
<h3>What is the quadratic function for a projectile's height?</h3>
Considering the height in meters, the equation is given by:
s(t) = -4.9t² + v(0)t + h(0)
In which:
- v(0) is the initial velocity, in m/s.
- h(0) is the initial height, in m.
In this problem, we have that v(0) = 39.2, h(0) = 0, hence the equation is:
s(t) = -4.9t² + 39.2t.
More can be learned about quadratic functions at brainly.com/question/24737967
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Answer:
Surface area = 6l^2
Volume = l^3
If total surface area increased by 2, then the length increased by 
Volume then is increased by (
l)^3 = 2
l^3
1 :2 
Which is not an option in the question so this question clearly has a problem.
First of all It's supposed to be "then" not "than," so I'm not sure who teaches math without even knowing this basic grammar.
Second of all, if the answer is 8:1 the question should be "If <u>each sides</u> of a cube is doubled" not "the lateral surface area." Come to think of it what even is lateral surface area of a cube if all sides of the cube is supposed to be same.
Or, if the answer is 2:1 then, it should be If height lateral surface area of a cube is doubled <u>by doubling the height and without changing the length and width</u>" But, then the the shape would no longer be a cube.
Who even wrote this garbage question what.
Answer:
4*3=12
12*4=
3*3=9
9*2=18
18+48=66
Step-by-step explanation:
Answer:
4.5 sq. units.
Step-by-step explanation:
The given curve is 
⇒
...... (1)
This curve passes through (0,0) point.
Now, the straight line is y = 3x - 6 ....... (2)
Now, solving (1) and (2) we get,

⇒ (y - 3)(y + 2) = 0
⇒ y = 3 or y = -2
We will consider y = 3.
Now, y = 3x - 6 has zero at x = 2.
Therefor, the required are = 
= ![\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%20%5B%7B%5Cfrac%7Bx%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%7D%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%7D%5D%5E%7B3%7D%20_%7B0%7D%20-%20%5B%5Cfrac%7B3x%5E%7B2%7D%20%7D%7B2%7D%20-%206x%20%5D%5E%7B3%7D%20_%7B2%7D)
= ![[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Csqrt%7B3%7D%5Ctimes%202%20%5Ctimes%203%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%7D%7B3%7D%5D%20-%20%5B13.5%20-%2018%20-%206%20%2B%2012%5D)
= 6 - 1.5
= 4.5 sq. units. (Answer)