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olya-2409 [2.1K]
3 years ago
9

5x - 4y = -8 x + 4y = -16

Mathematics
1 answer:
kati45 [8]3 years ago
7 0

Answer:

(-4 , -3)

Step-by-step explanation:

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Please answer the question in the screen shot right
ss7ja [257]
Its decagon. cause it has 10 corners.

5 0
4 years ago
A rocket is launched from the ground at an initial velocity of 39.2 meters per second. Which equation can be used to model the h
Naya [18.7K]

The quadratic equation that models the height of the rocket after t seconds is:

s(t) = -4.9t² + 39.2t.

<h3>What is the quadratic function for a projectile's height?</h3>

Considering the height in meters, the equation is given by:

s(t) = -4.9t² + v(0)t + h(0)

In which:

  • v(0) is the initial velocity, in m/s.
  • h(0) is the initial height, in m.

In this problem, we have that v(0) = 39.2, h(0) = 0, hence the equation is:

s(t) = -4.9t² + 39.2t.

More can be learned about quadratic functions at brainly.com/question/24737967

#SPJ1

8 0
2 years ago
Find the answer given below​
Anastasy [175]

Answer:

Surface area = 6l^2

Volume = l^3

If total surface area increased by 2, then the length increased by \sqrt{2}

Volume then is increased by (\sqrt{2}l)^3 = 2\sqrt{2}l^3

1 :2 \sqrt{2}

Which is not an option in the question so this question clearly has a problem.

First of all It's supposed to be "then" not "than," so I'm not sure who teaches math without even knowing this basic grammar.

Second of all, if the answer is 8:1 the question should be "If <u>each sides</u> of a cube is doubled" not "the lateral surface area." Come to think of it what even is lateral surface area of a cube if all sides of the cube is supposed to be same.

Or, if the answer is 2:1 then, it should be If height lateral surface area of a cube is doubled <u>by doubling the height and without changing the length and width</u>"  But, then the the shape would no longer be a cube.

Who even wrote this garbage question what.

6 0
3 years ago
PLEASE HELP (question is in picture)
HACTEHA [7]

Answer:

4*3=12

12*4=

3*3=9

9*2=18

18+48=66

Step-by-step explanation:

8 0
3 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
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