All categories

3 years ago

Write the equation for the line that goes through the point (5, 12) with a slope m = 10

Mathematics

1 answer:

Iteru [2.4K]3 years ago

3 0

Answer:

<u>Point-slope form</u>: y - 12 = 10 (x - 5)

<u>Slope-Intercept form</u>: y= 10x - 38

Step-by-step explanation:

im not fully sure which equation ur looking for but i think thats right lol. hopefully this helps ! :)

You might be interested in

I will mark brainlist for this science question please. I need to figure out where to put where. And what percentages. Your choi

ozzi

Answer:

Long wings: 0

Short wings: 100

Step-by-step explanation:

Genotype of the flies: ww

The cross will yield the genotype ww and the flies will express the recessive phenotype which is short wings.

The probability for long wings will be 0 as there is no dominant allele present. The probability for short wings will be 100 as all the flies will have short wings.

Hope that helps.

3 0

3 years ago

What is the domain of the relation?

amm1812

Domain:

{-4, -2, -1 , 1, 4}

Hope it helps

3 0

4 years ago

Jack broke apart 5×216 as (5×200) (5×16) to multiply mentally. What strategy did Jack use?

PSYCHO15rus [73]

Breaking the it down- simplifying

5 0

3 years ago

Help pls lol

Kobotan [32]

Answer:

Options :

Step-by-step explanation:

1200m + 500 = 10700

5 0

3 years ago

1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is $53.13\°$

Part 2) The surface area of the pyramid is $288\ cm^{2}$

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

$sin(x)=\frac{16}{20}$

$x=arcsin(\frac{16}{20})=53.13\°$

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

$SA=b^{2}+4[\frac{1}{2}(b)(h)]$

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

$h=b/2$ -------> by an 45° angle

$b=2h$

$sin(45\°)=\frac{h}{6\sqrt{2}}$

$h=6\sqrt{2}(sin(45\°))=6\ cm$

Find the value of b

$b=2(6)=12\ cm$

Find the surface area

$SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}$

3 0

4 years ago

Write the equation for the line that goes through the point (5, 12) with a slope m = 10​

Write the equation for the line that goes through the point (5, 12) with a slope m = 10