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Naya [18.7K]
3 years ago
14

Find the slope of ( 3,7 ) ( 4,10 )

Mathematics
1 answer:
Dominik [7]3 years ago
6 0
The slope is 3.

10 - 7 = 3
4 - 3 = 1

Final step is to do 3 divided by 1 and you get 3.
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Novay_Z [31]

Due to the Triangle Angle Sum Theorem, we know that the sum of the interior angles of a triangle equals 180 degrees, therefore,

180 = m<1 + m<2 + m<3

180 - m<3 = m<1 + m<2

But, we also know that m<4 + m<3 = 180 degrees.

180 = m<3 + m<4

180 - m<3 = m<4

Both m<4 and m<1 + m<2  equals 180 - m<3

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The correct option is;
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Alexeev081 [22]

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Sketch the region that is common to the graphs of x ≥ 2,
Oliga [24]

a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

  • The graph of x ≥ 2 is the region right of the line x = 2.
  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

  • height = 4 units and
  • base = 4 units

So, its area = 1/2 × height × base

= 1/2 × 4 units × 4 units

= 1/2 × 16 units²

= 8 units²

So, the area of the common region of the graphs is 8 units²

Learn more about region common to graphs here:

brainly.com/question/27932405

#SPJ1

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kyle regalara 16 figuras y le quedara 3/4 de ellas

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