Question

What is an equation of the line that passes through the points (3, 4) and (-4, -3)?

Answer 1

Y=Mx+c
Mx=y2-y1/x2-x1
Mx=-3-4/-4-3=1

Mx=1

Y=x+c (now pick and replace one of the points to find c which the y-intercept)

3=4+c
C=-1

Final answer = y=x-1

I really hope you understand my explanation and if you can give me a brainliest, I would really appreciate it!!

Answer 2

Answer:

y = x + 1

Step-by-step explanation:

Equation of line : y = mx + b, m = slope, b = y intercept

Find slope, m

$Slope, m = \frac{y_2 - y_1}{x_2 - x_1}$

             $= \frac{-3 - 4}{-4 - 3} \\\\=\frac{-7}{-7}\\\\=\frac{7}{7}\\\\= 1$

Equation of line : $(x_1, y_1) = ( 3, 4 )$

[ You can choose any set of points from the given points. ]

                 $(y - y_1) = m(x - x_1)$

                 $(y - 4 ) = 1 \times ( x - 3)\\\\y - 4 = x - 3\\\\y = x - 3 + 4 \\\\y = x + 1$