Answer:
1) ![P=4s](https://tex.z-dn.net/?f=P%3D4s)
2) ![P=4\sqrt{A}](https://tex.z-dn.net/?f=P%3D4%5Csqrt%7BA%7D)
see the explanation
Step-by-step explanation:
we know that
The perimeter of the square is equal to
![P=4s](https://tex.z-dn.net/?f=P%3D4s)
where
s is the length side of the square
we have
![P=15,2\ cm](https://tex.z-dn.net/?f=P%3D15%2C2%5C%20cm)
substitute
![15.2=4s](https://tex.z-dn.net/?f=15.2%3D4s)
solve for s
![s=15.2/4=3.8\ cm](https://tex.z-dn.net/?f=s%3D15.2%2F4%3D3.8%5C%20cm)
The area of a square is equal to
![A=s^2](https://tex.z-dn.net/?f=A%3Ds%5E2)
substitute
![A=3.8^2=14.44\ cm^2](https://tex.z-dn.net/?f=A%3D3.8%5E2%3D14.44%5C%20cm%5E2)
we have that
![s=\sqrt{A}](https://tex.z-dn.net/?f=s%3D%5Csqrt%7BA%7D)
therefore
2 equations that can determine the perimeter of the square are
1)
----> ![P=4(3.8)=15.2\ cm](https://tex.z-dn.net/?f=P%3D4%283.8%29%3D15.2%5C%20cm)
2)
----> ![P=4\sqrt{14.44}=15.2\ cm](https://tex.z-dn.net/?f=P%3D4%5Csqrt%7B14.44%7D%3D15.2%5C%20cm)
627.
you would have to do this on your own in order to find this out bud.
You can use the change of base formula to get
![\log_2(100) = \frac{\log(100)}{\log(2)} \approx 6.643856](https://tex.z-dn.net/?f=%5Clog_2%28100%29%20%3D%20%5Cfrac%7B%5Clog%28100%29%7D%7B%5Clog%282%29%7D%20%5Capprox%206.643856)
and also
![\log_6(20) = \frac{\log(20)}{\log(6)} \approx 1.671950](https://tex.z-dn.net/?f=%5Clog_6%2820%29%20%3D%20%5Cfrac%7B%5Clog%2820%29%7D%7B%5Clog%286%29%7D%20%5Capprox%201.671950)
In general, the change of base formula is
![\log_b(x) = \frac{\log(x)}{\log(b)}](https://tex.z-dn.net/?f=%5Clog_b%28x%29%20%3D%20%5Cfrac%7B%5Clog%28x%29%7D%7B%5Clog%28b%29%7D)
Answer:
8 / 0.000001
Step-by-step explanation:
8 / 0.0001 is 80000 so just put more zeros to make a greater one.